Algebra. Graph y=2x. y = 2x y = 2 x. Use the slope-intercept form to find the slope and y-intercept. Tap for more steps... Slope: 2 2. y-intercept: (0,0) ( 0, 0) Any line can be graphed using two points. Select two x x values, and plug them into the equation to find the corresponding y y values.Step 1: Finding the Vertex. Step 2: Finding two points to left of axis of symmetry. Step 3: Reflecting two points to get points right of axis of symmetry. Step 4: Plotting the Points (with table) Step 5: Graphing the Parabola. In order to graph , we can follow the steps: Step 1) Find the vertex (the vertex is the either the highest or lowest ...First, graph a line with the equation y = 2 3 x −1. This equation is in the form y = mx + b. 2 3 is the slope and −1 is the y-intercept. graph {2/3x-1 [-10, 10, -5, 5]} However, we are graphing an inequality so we're gonna have to shade either the area above the line or below the line. First, let's look at the inequality symbols. > Greater ...Find the properties of the given parabola. Tap for more steps... Direction: Opens Right. Vertex: (1,3) ( 1, 3) Focus: (5 4,3) ( 5 4, 3) Axis of Symmetry: y = 3 y = 3. Directrix: x = 3 4 x = 3 4. Select a few x x values, and plug them into the equation to find the corresponding y y values. The x x values should be selected around the vertex.Step 1: Finding the Vertex. Step 2: Finding two points to left of axis of symmetry. Step 3: Reflecting two points to get points right of axis of symmetry. Step 4: Plotting the Points (with table) Step 5: Graphing the Parabola. In order to graph , we can follow the steps: Step 1) Find the vertex (the vertex is the either the highest or lowest ...Graph y=-2. Step 1. Use the slope-intercept form to find the slope and y-intercept. Tap for more steps... Step 1.1. The slope-intercept form is , where is the slope ...Explanation: The student asked for the graph of y= (x-3)^2+1. This formula is a parabola with a minimum point, shifted horizontally and vertically in the coordinate plane. The formula in general form is y=a (x-h)^2+k, where 'h' is the x-coordinate of the vertex, 'k' is the y-coordinate and 'a' affects the 'width' and 'direction' of the parabola.Graph y-1=2 (x-2) | Mathway. Algebra Examples. Popular Problems. Algebra. Graph y-1=2 (x-2) y − 1 = 2(x − 2) y - 1 = 2 ( x - 2) Move all terms not containing y y to the right side …Step 2.11.1.2. Multiply by . Step 2.11.2. Subtract from . Step 2.11.3. The final answer is . Step 2.12. The value at is . Step 2.13. Graph the parabola using its properties and the selected points. Step 3. Graph the parabola using its properties and the selected points. Direction: Opens Up. Vertex: Focus:Graph y=(2x)/(x^2-1) Step 1. Find where the expression is undefined. Step 2. Since as from the left and as from the right, then is a vertical asymptote. ... 2. If , then the horizontal asymptote is the line. 3. If , then there is no horizontal asymptote (there is an oblique asymptote). Step 6. Find and .Step 2.1.3. Convert to decimal. Step 2.2. Substitute the value into . In this case, the point is . Tap for more steps... Step 2.2.1. Replace the variable with in the expression. ... Graph the parabola using its properties and the selected points. Step 3. Graph the parabola using its properties and the selected points. Direction: Opens Right ...Trigonometry. Graph y=tan (2x) y = tan (2x) y = tan ( 2 x) Find the asymptotes. Tap for more steps... No Horizontal Asymptotes. No Oblique Asymptotes. Vertical Asymptotes: x = π 4 + πn 2 x = π 4 + π n 2 where n n is an integer. Use the form atan(bx−c)+ d a tan ( b x - c) + d to find the variables used to find the amplitude, period, phase ...Graph y - 7 = -3(x - 1) There are many ways to do this, such as setting a point and doing some calculation but I will use another way. Recall slope is equal to change of y-coordinate for every one unit change in the x-coordinate. So if the slope is -3, it means for every 1 unit increase in x-coordinate, y-coordinate will reduce by 3 unit (-3).Algebra. Graph y^2-x^2=1. y2 − x2 = 1 y 2 - x 2 = 1. Simplify each term in the equation in order to set the right side equal to 1 1. The standard form of an ellipse or hyperbola requires the right side of the equation be 1 1. y2 − x2 1 = 1 y 2 - x 2 1 = 1. This is the form of a hyperbola. Use this form to determine the values used to find ...Pre-Algebra. Graph y=2.5x+1.5. y = 2.5x + 1.5 y = 2.5 x + 1.5. Graph. y = 2.5x+1.5 y = 2.5 x + 1.5. Free math problem solver answers your algebra, geometry, trigonometry, calculus, and statistics homework questions with step-by-step explanations, just like a math tutor.A short cut for implicit differentiation is using the partial derivative (∂/∂x). When you use the partial derivative, you treat all the variables, except the one you are differentiating with respect to, like a constant. For example ∂/∂x [2xy + y^2] = 2y. In this case, y is treated as a constant. Here is another example: ∂/∂y [2xy ...Graph y=2cos(x-pi/3) Step 1. Use the form to find the variables used to find the amplitude, period, phase shift, and vertical shift. Step 2. Find the amplitude . Amplitude: ... Step 6.5.2.1. Combine the numerators over the common denominator. Step 6.5.2.2. Subtract from . Step 6.5.2.3. Cancel the common factor of and . Tap for more steps ...The correct option is i.e., .. Further explanation: The linear equation of the line is where, is the slope of the line and is the -intercept of the line.. Suppose the line passes through the two points and .. Therefore, the slope of the line can be calculated as follows:. The symbol represents the solution set lies above the dotted line and the symbol represents the solution set below the ...y-intercept: (0,4) ( 0, 4) Any line can be graphed using two points. Select two x x values, and plug them into the equation to find the corresponding y y values. Tap for more steps... x y 0 4 2 5 x y 0 4 2 5. Graph the line using the slope and the y-intercept, or the points. Slope: 1 2 1 2. y-intercept: (0,4) ( 0, 4) x y 0 4 2 5 x y 0 4 2 5.Step 2.1.3. Convert to decimal. Step 2.2. Substitute the value into . In this case, the point is . Tap for more steps... Step 2.2.1. Replace the variable with in the expression. ... Graph the parabola using its properties and the selected points. Step 3. Graph the parabola using its properties and the selected points. Direction: Opens Right ...EDIT: After looking at @Jean Marie's answer below, I plotted the graph of $$(x^2 + y^2) - \frac{x^6 + y^6}{6} = 1,$$ reasoning that near the origin a few terms of the Taylor series might help. The resulting graph was quite similar to the strange shape near the origin in thing above. Somewhat unexpectedly (at least for a callow neophyte like me), a much closer approximation (shapewise) was ...Graph the Hyperbola x^2 - y^2 = 1 and Find the Domain and RangeIf you enjoyed this video please consider liking, sharing, and subscribing.Udemy Courses Via M...Graph a Linear Equation by Plotting Points. There are several methods that can be used to graph a linear equation. The method we used at the start of this section to graph is called plotting points, or the Point-Plotting Method.. Let's graph the equation y = 2 x + 1 y = 2 x + 1 by plotting points.. We start by finding three points that are solutions to the equation.Algebra. Graph (x^2)/16+ (y^2)/4=1. x2 16 + y2 4 = 1 x 2 16 + y 2 4 = 1. Simplify each term in the equation in order to set the right side equal to 1 1. The standard form of an ellipse or hyperbola requires the right side of the equation be 1 1. x2 16 + y2 4 = 1 x 2 16 + y 2 4 = 1. This is the form of an ellipse.A straight line with slope of 1/2 and y-intercept of 2 The equation of a straight line with slope (m) and y-intercept (c) form is: y=mx+c In this example: y=1/2x+2 So, m=1/2 and c=2 Thus the graph of y is a straight line with slope of 1/2 and y-intercept of 2 as below. graph{x/2+2 [-5.207, 5.893, -1, 4.55]}Graph the parabola, y =x^2+1 by finding the turning point and using a table to find values for x and yThere are so many types of graphs and charts at your disposal, how do you know which should present your data? Here are 14 examples and why to use them. Trusted by business builder...y-intercept: (0,7) ( 0, 7) Any line can be graphed using two points. Select two x x values, and plug them into the equation to find the corresponding y y values. Tap for more steps... x y 0 7 2 8 x y 0 7 2 8. Graph the line using the slope and the y-intercept, or the points. Slope: 1 2 1 2. y-intercept: (0,7) ( 0, 7)sin (x)+cos (y)=0.5. 2x−3y=1. cos (x^2)=y. (x−3) (x+3)=y^2. y=x^2. If you don't include an equals sign, it will assume you mean " =0 ". It has not been well tested, so have fun with it, but don't trust it. If it gives you problems, let me know. Note: it may take a few seconds to finish, because it has to do lots of calculations.Graph y=(x-8)^2. Step 1. Find the properties of the given parabola. Tap for more steps... Step 1.1. Use the vertex form, , to determine the values of , , and . Step 1.2. Since the value of is positive, the parabola opens up. Opens Up. Step 1.3. Find the vertex. Step 1.4. Find , the distance from the vertex to the focus.Graph y=2cos(2x) Step 1. Use the form to find the variables used to find the amplitude, period, phase shift, and vertical shift. Step 2. Find the amplitude . Amplitude: ... Step 6.4.2.1.3. Rewrite the expression. Step 6.4.2.2. Apply the reference angle by finding the angle with equivalent trig values in the first quadrant. Step 6.4.2.3.Mar 6, 2017 · Graph the parabola, y =x^2+1 by finding the turning point and using a table to find values for x and y.Algebra. Graph y=2x+1. y = 2x + 1 y = 2 x + 1. Use the slope-intercept form to find the slope and y-intercept. Tap for more steps... Slope: 2 2. y-intercept: (0,1) ( 0, 1) Any line can be graphed using two points. Select two x x values, and plug them into the equation to find the corresponding y y values.Trigonometry. Graph y=2sin (1/2x) y = 2sin( 1 2 x) y = 2 sin ( 1 2 x) Use the form asin(bx−c)+ d a sin ( b x - c) + d to find the variables used to find the amplitude, period, phase shift, and vertical shift. a = 2 a = 2. b = 1 2 b = 1 2. c = 0 c = 0. d = 0 d = 0. Find the amplitude |a| | a |.y = −x2 − 4x − 1 y = - x 2 - 4 x - 1. Find the properties of the given parabola. Tap for more steps... Direction: Opens Down. Vertex: (−2,3) ( - 2, 3) Focus: (−2, 11 4) ( - 2, 11 4) Axis of Symmetry: x = −2 x = - 2. Directrix: y = 13 4 y = 13 4. Select a few x x values, and plug them into the equation to find the corresponding y y ...Step 1: Finding the Vertex. Step 2: Finding two points to left of axis of symmetry. Step 3: Reflecting two points to get points right of axis of symmetry. Step 4: Plotting the Points (with table) Step 5: Graphing the Parabola. In order to graph , we can follow the steps: Step 1) Find the vertex (the vertex is the either the highest or lowest ...Facebook today unveiled a new search feature for its flagship product, facebook.com, that creates new competition for online information providers ranging from search engines to re...Pre-Algebra. Graph y=2 (x+1)^2-8. y = 2(x + 1)2 − 8 y = 2 ( x + 1) 2 - 8. Find the properties of the given parabola. Tap for more steps... Direction: Opens Up. Vertex: (−1,−8) ( - 1, - 8) Focus: (−1,−63 8) ( - 1, - 63 8) Axis of Symmetry: x = −1 x = - 1.Pre-Algebra. Graph y=x+1. y = x + 1 y = x + 1. Use the slope-intercept form to find the slope and y-intercept. Tap for more steps... Slope: 1 1. y-intercept: (0,1) ( 0, 1) Any line can be graphed using two points. Select two x x values, and plug them into the equation to find the corresponding y y values.Algebra. Graph y=2* (1/2)^x. y = 2 ⋅ ( 1 2)x y = 2 ⋅ ( 1 2) x. Exponential functions have a horizontal asymptote. The equation of the horizontal asymptote is y = 0 y = 0. Horizontal Asymptote: y = 0 y = 0. Free math problem solver answers your algebra, geometry, trigonometry, calculus, and statistics homework questions with step-by-step ...Graph y+3=1/2*(x+2) Step 1. Move all terms not containing to the right side of the equation. ... Step 1.2. Subtract from . Step 2. Rewrite in slope-intercept form. Tap for more steps... Step 2.1. The slope-intercept form is , where is the slope and is the y-intercept. Step 2.2. Reorder terms. Step 3. Use the slope-intercept form to find the ...Graph y-3=1/4*(x+2) Step 1. Move all terms not containing to the right side of the equation. Tap for more steps... Step 1.1. Add to both sides of the equation. Step 1.2. To write as a fraction with a common denominator, multiply by . Step 1.3. Combine and . Step 1.4. Combine the numerators over the common denominator.Step 2.1. The slope-intercept form is , where is the slope and is the y-intercept. ... Graph the line using the slope and the y-intercept, or the points. Slope:To solve a system of linear equations by graphing. Graph the first equation. Graph the second equation on the same rectangular coordinate system. Determine whether the lines intersect, are parallel, or are the same line. Identify the solution to the system. If the lines intersect, identify the point of intersection.Graph y=2cos(2x) Step 1. Use the form to find the variables used to find the amplitude, period, phase shift, and vertical shift. Step 2. Find the amplitude . Amplitude: ... Step 6.4.2.1.3. Rewrite the expression. Step 6.4.2.2. Apply the reference angle by finding the angle with equivalent trig values in the first quadrant. Step 6.4.2.3.Trigonometry. Graph y=2 (1/2x) y = 2( 1 2 x) y = 2 ( 1 2 x) Use the slope-intercept form to find the slope and y-intercept. Tap for more steps... Slope: 1 1. y-intercept: (0,0) ( 0, 0) Any line can be graphed using two points. Select two x x values, and plug them into the equation to find the corresponding y y values.Step 2.1. The slope-intercept form is , where is the slope and is the y-intercept. ... Graph the line using the slope and the y-intercept, or the points. Slope:In today’s data-driven world, effective data presentation is key to conveying information in a clear and concise manner. One powerful tool that can assist in this process is a free...Graph y=1/2*cos(x-pi/2) Step 1. Use the form to find the variables used to find the amplitude, period, phase shift, and vertical shift. Step 2. Find the amplitude . Amplitude: ... Step 6.5.2.1.4. Subtract full rotations of until the angle is greater than or equal to and less than . Step 6.5.2.1.5. The exact value of is . Step 6.5.2.2. The final ...In this video we'll draw the graph for y = 2. It is perhaps easiest to think of y=2 as being a line where all the values of y are 2. That means for any val...To solve this problem, we simply need to plot the cosine graph. Graph of Cosine. The graph of cosine can easily be plotted and we can compare both together. Kindly check the attached image and we can easily see the graph of . is option A. Comparing the asymptotes together, it reveals more information on that. Learn more on graph of cosine here;Tap for more steps... Direction: Opens Up. Vertex: (−1,−8) ( - 1, - 8) Focus: (−1,−63 8) ( - 1, - 63 8) Axis of Symmetry: x = −1 x = - 1. Directrix: y = −65 8 y = - 65 8. Select a few x x values, and plug them into the equation to find the corresponding y y values. The x x values should be selected around the vertex.China says its uncrewed craft has successfully landed on the far side of the Moon - an unexplored place almost no-one tries to go. The Chang'e 6 touched down in the South …Please Subscribe here, thank you!!! https://goo.gl/JQ8NysThe Graphs of y = 1/x and y = 1/x^2 College AlgebraGraph y^2-1. y2 − 1 y 2 - 1. Find the properties of the given parabola. Tap for more steps... Direction: Opens Right. Vertex: (−1,0) ( - 1, 0) Focus: (−3 4,0) ( - 3 4, 0) Axis of …Answer link. See a solution process below: The equation y = 2 says for any value of x the y value is 2. Therefore, two points on this line are: (-2, 2) and (2,2 ) We can first plot these points: graph { ( (x+2)^2+ (y-2)^2-0.04) ( (x-2)^2+ (y-2)^2-0.04)=0 [-10, 10, -5, 5]} Now, we can draw a straight line through the two points to graph the line ...In this video we'll draw the graph for y = x^2 + 1 using a table of values .First, we will use a table of values to plot points on the graph. Once we have tw...2. Answer: The graph in the attached figure. Step-by-step explanation: we have. The solution of the inequality is the shaded area above the solid line of the equation of the parabola. The vertex of the parabola is the point (0,-1) The parabola open downward (vertex is a maximum) using a graphing tool.Rewrite in slope-intercept form. Tap for more steps... y = 2 7x+ 1 y = 2 7 x + 1. Use the slope-intercept form to find the slope and y-intercept. Tap for more steps... Slope: 2 7 2 7. y-intercept: (0,1) ( 0, 1) Any line can be graphed using two points. Select two x x values, and plug them into the equation to find the corresponding y y values.Explore math with our beautiful, free online graphing calculator. Graph functions, plot points, visualize algebraic equations, add sliders, animate graphs, and more.y = x2 − 2x − 2 y = x 2 - 2 x - 2. Find the properties of the given parabola. Tap for more steps... Direction: Opens Up. Vertex: (1,−3) ( 1, - 3) Focus: (1,−11 4) ( 1, - 11 4) Axis of Symmetry: x = 1 x = 1. Directrix: y = −13 4 y = - 13 4. Select a few x x values, and plug them into the equation to find the corresponding y y values.y = x2 − 2x − 2 y = x 2 - 2 x - 2. Find the properties of the given parabola. Tap for more steps... Direction: Opens Up. Vertex: (1,−3) ( 1, - 3) Focus: (1,−11 4) ( 1, - 11 4) Axis of Symmetry: x = 1 x = 1. Directrix: y = −13 4 y = - 13 4. Select a few x x values, and plug them into the equation to find the corresponding y y values.y = −x2 − 4x − 1 y = - x 2 - 4 x - 1. Find the properties of the given parabola. Tap for more steps... Direction: Opens Down. Vertex: (−2,3) ( - 2, 3) Focus: (−2, 11 4) ( - 2, 11 4) Axis of Symmetry: x = −2 x = - 2. Directrix: y = 13 4 y = 13 4. Select a few x x values, and plug them into the equation to find the corresponding y y ...